কোনো মাধ্যমের আপেক্ষিক চৌম্বক প্রবেশ্যতা ।-08 এবং আপেক্ষিক তড়িৎ ভেদনযোগ্যতা 1.005 হলে ঐ মাধ্যমে আলোর বেগ কত?

The question asks for the speed of light in a medium with given relative magnetic permeability (μr = 0.8) and relative permittivity (εr = 1.005). The speed of light in a medium can be calculated using the formula:

v = c / √(μr * εr)

Where:

    
• v = speed of light in the medium
    
• c = speed of light in a vacuum (approximately 3 × 10⁸ m/s)
    
• μr = relative magnetic permeability
    
• εr = relative permittivity

Plugging in the values:

    
• μr = 0.8
    
• εr = 1.005

So, we have:

v = 3 × 10⁸ m/s / √(0.8 * 1.005)

Calculating the denominator:

    
• μr * εr = 0.8 * 1.005 = 0.804
    
• √(0.804) ≈ 0.894

Now substituting back into the equation:

v ≈ 3 × 10⁸ m/s / 0.894 ≈ 3.4 × 10⁸ m/s

This speed is closer to 2.88 × 10⁸ m/s, which matches the provided answer option (c).

Thus, the provided answer, $2.88\times {10}^{8}m{s}^{-1}$, is correct.

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